题目链接：
思路：就是一个简单的图书管理系统模拟，book的布尔值显示是否在图书馆；如果有一个人还书，那么那个人的拥有书的信息也要修改。
View Code 1 #include2 #include 3 #include 4 #include 5 using namespace std; 6 #define MAXN 100000+10 7 bool book[MAXN]; 8 int n,m; 9 struct Person{10 int book[11];11 int _count;12 }Per[MAXN/10];13 14 15 int main(){16 int _case;17 while(~scanf("%d%d",&n,&m)){18 memset(book,true,sizeof(book));19 memset(Per,0,sizeof(Per));20 scanf("%d",&_case);21 while(_case--){22 char str[10];23 scanf("%s",str);24 int x,y;25 if(str[0]=='R'){26 scanf("%d",&x);27 if(book[x]){puts("The book is already in the library");continue;}28 else {29 book[x]=true;30 puts("Return success");31 bool flag=true;32 for(int i=1;i<=m&&flag;i++){33 int k=Per[i]._count; 34 for(int j=1;j<=k;j++)if(Per[i].book[j]==x){35 for(int l=j+1;l<=k;l++){Per[i].book[l-1]=Per[i].book[l];}36 Per[i]._count--;37 flag=false;38 break;39 }40 }41 }42 }else if(str[0]=='B'){43 scanf("%d%d",&x,&y);44 int count;45 if(!book[y]){puts("The book is not in the library now");continue;}46 else if(Per[x]._count==9){puts("You are not allowed to borrow any more");continue;}47 else {book[y]=false;count=++Per[x]._count;Per[x].book[count]=y;puts("Borrow success");continue;}48 }else {49 scanf("%d",&x);50 if(Per[x]._count==0){puts("Empty");continue;}51 else {52 sort(Per[x].book+1,Per[x].book+Per[x]._count+1);53 for(int i=1;i